Swinger Throwout Action

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Brian Manzella

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Good answer, wanole.

Yes, Ray, the secret is the INWARD force—you turning toward the center with the right axis tilt—CAUSES the outward force.

This outward force will—if you LET it—uncock your left wrist. And due to the sweetspot location on the club, transfer the speed of this uncocking to the rolling left hand.

OK, but what about the left arm?

The left arm will NEVER come off the chest if the chest keeps going with the arm.

Huh???

The left shoulder goes up and BACK through impact, ALLOWing the left arm to blast off.

So keep your head back, and make your left shoulder go backward and inward and FEEL the whole club and arm assembly try to PULL the arms right out of there sockets.

Or in english...

Swing as if you were a dime-store mannequin, and you want the left arm to disconnect and tumble down the fairway.
 

bts

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quote:Originally posted by rbaumgolf

What causes this to just "happen"

Blasting off the chest?
The "release" of "accmulater lag" due to the slowing down of the pivot/shoulder turn.

quote:I don't seem to have a chest blastoff???
You need to "load" it (let the left upper arm press against the left upper chest) first and sustain it coming dowm.
quote:Originally posted by DDL

So does the 'blasstoff' occur after impact for a swinger?
Ideally, yes.
 
If we are a swinger, should as we rotate through the release and impact the order of release of the accumulators be #2, #3 then #4?
 
4,1,2,3 6-m-1 yellow book, if I understand this correctly...

#4 follows the pivot, 6-b-4-0

#3 transfers the power, I think of it as the rotation of the left forearm to maintain left wrist position. If not, hello flipper.

edit

w'respect to release, brian did a video addressing this.

Essentially there are two accumulators involved with the swinger's sequential release, #2 and #3, action of the uncoking wrist and the turning wrist.
 
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