mandrin
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In two succeeding posts by ThinkingPlus
Physics 101 answer
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Basically, since this is an elastic collision, momentum is not strictly conserved, but it is close enough for our purposes. You can also approximate Mclub with the mass of the clubhead alone since the impact interaction occurs over such a short time.
Newton's 1st Law
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Lag pressure maintained through impact will result in a collision that is more inelastic (less lossy) than if one had a clubhead moving with a constant velocity (my assertion, et al.).
In the first post it is clear that the clubhead is considered a free mass. (this is against TGM philosophy.) In the second post it is however just the opposite. An obvious and very clear contradiction in two adjacent posts.
Also in the first post it is stated that in an elastic collision momentum is not conserved. This is a gross error. Momentum is ALWAYS conserved, both in elastic and inelastic collisions.
Moreover in the second post it is stated that there is less loss in a more inelastic collision. This is a gross error. It is just the opposite. Kinetic energy is conserved in an elastic collision and is not in an inelastic collision.
Physics 101 answer
-------
Basically, since this is an elastic collision, momentum is not strictly conserved, but it is close enough for our purposes. You can also approximate Mclub with the mass of the clubhead alone since the impact interaction occurs over such a short time.
Newton's 1st Law
-----
Lag pressure maintained through impact will result in a collision that is more inelastic (less lossy) than if one had a clubhead moving with a constant velocity (my assertion, et al.).
In the first post it is clear that the clubhead is considered a free mass. (this is against TGM philosophy.) In the second post it is however just the opposite. An obvious and very clear contradiction in two adjacent posts.
Also in the first post it is stated that in an elastic collision momentum is not conserved. This is a gross error. Momentum is ALWAYS conserved, both in elastic and inelastic collisions.
Moreover in the second post it is stated that there is less loss in a more inelastic collision. This is a gross error. It is just the opposite. Kinetic energy is conserved in an elastic collision and is not in an inelastic collision.
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