Golfbulldog
Unfortunately, I don't have the expertise to define the term effective mass as it applies to the golf swing, but I can envisage what it refers to in simplistic conceptual terms.
Consider the clubhead in the mid downswing. It is travelling down an inclined arc towards the ground at a certain speed at any specific time-point in the mid-downswing. The clubhead has a finite mass, but the force of its movement in the direction of the ground is obviously affected by its speed of movement, and its effective mass (relative to the ground) is a combination of its finite mass and the speed vector that is directed in the direction of the ground. Its effective mass essentially determines the magnitude of the force that would be needed to change its path direction. I think that the same principle applies to torso movements in the downswing. When Tiger Woods starts the downswing, he uses torso muscular forces to push his torso down towards the ground and also left-laterally. That added muscular force causes the effective mass of the moving torso to be different to the static COG mass at any time-point in the downswing, because the body is always moving throughout the downswing and the body movement has a force vector that is directed both to the left and groundwards. I don't know how to calculate the magnitude of this force, but I can perceive its presence when I swing a golf club. When I am approaching impact, my torso (which has a certain degree of secondary axis tilt) is well behind the center of the stance, but there is no doubt in my mind that the force over the left foot (directed groundwards) far exceeds the force over the right foot. I can therefore easily understand Hogan's assertion that 85% of the effective mass is over the left foot as one nears impact.
Jeff.
Unfortunately, I don't have the expertise to define the term effective mass as it applies to the golf swing, but I can envisage what it refers to in simplistic conceptual terms.
Consider the clubhead in the mid downswing. It is travelling down an inclined arc towards the ground at a certain speed at any specific time-point in the mid-downswing. The clubhead has a finite mass, but the force of its movement in the direction of the ground is obviously affected by its speed of movement, and its effective mass (relative to the ground) is a combination of its finite mass and the speed vector that is directed in the direction of the ground. Its effective mass essentially determines the magnitude of the force that would be needed to change its path direction. I think that the same principle applies to torso movements in the downswing. When Tiger Woods starts the downswing, he uses torso muscular forces to push his torso down towards the ground and also left-laterally. That added muscular force causes the effective mass of the moving torso to be different to the static COG mass at any time-point in the downswing, because the body is always moving throughout the downswing and the body movement has a force vector that is directed both to the left and groundwards. I don't know how to calculate the magnitude of this force, but I can perceive its presence when I swing a golf club. When I am approaching impact, my torso (which has a certain degree of secondary axis tilt) is well behind the center of the stance, but there is no doubt in my mind that the force over the left foot (directed groundwards) far exceeds the force over the right foot. I can therefore easily understand Hogan's assertion that 85% of the effective mass is over the left foot as one nears impact.
Jeff.