quote:Originally posted by mandrin
NAT, would you mind explaining what you mean when you use Homer's concept - 'Effective Clubhead Mass', (2-M-2). I am aware of 'effective mass' as used in physics and quantum mechanics with regard to electrons and semiconductors, but how do you change the 'effective mass' of a clubhead in a golf swing?
Mandrin,
Not NAT, I'm afraid, but "effective mass" is a mechanical concept that's very easily demonstrated with a putter. If F = ma, then effective mass is just the ratio of the force and the acceleration, i.e. m[e] = F/a. When Tiger explains how to "deaden" his putts by hitting the ball with the toe of his club, he's using the same acceleration of the putter head while reducing the force on the ball. Although the actual mass of the putter head hasn't changed, its effective mass has (in this case) decreased proportionally to the force.
In theory, at least, other effects could increase the force to make the effective mass greater than the actual mass of the clubhead. There are enough force-reducing flaws in my golf stroke that I'd be happy just making them the same!